Optimal. Leaf size=262 \[ \frac{8 i x \text{Li}_2\left (-i e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d^2 \sqrt{a \cos (c+d x)+a}}-\frac{8 i x \text{Li}_2\left (i e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d^2 \sqrt{a \cos (c+d x)+a}}-\frac{16 \text{Li}_3\left (-i e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d^3 \sqrt{a \cos (c+d x)+a}}+\frac{16 \text{Li}_3\left (i e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d^3 \sqrt{a \cos (c+d x)+a}}-\frac{4 i x^2 \cos \left (\frac{c}{2}+\frac{d x}{2}\right ) \tan ^{-1}\left (e^{\frac{1}{2} i (c+d x)}\right )}{d \sqrt{a \cos (c+d x)+a}} \]
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Rubi [A] time = 0.167395, antiderivative size = 262, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.278, Rules used = {3319, 4181, 2531, 2282, 6589} \[ \frac{8 i x \text{Li}_2\left (-i e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d^2 \sqrt{a \cos (c+d x)+a}}-\frac{8 i x \text{Li}_2\left (i e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d^2 \sqrt{a \cos (c+d x)+a}}-\frac{16 \text{Li}_3\left (-i e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d^3 \sqrt{a \cos (c+d x)+a}}+\frac{16 \text{Li}_3\left (i e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d^3 \sqrt{a \cos (c+d x)+a}}-\frac{4 i x^2 \cos \left (\frac{c}{2}+\frac{d x}{2}\right ) \tan ^{-1}\left (e^{\frac{1}{2} i (c+d x)}\right )}{d \sqrt{a \cos (c+d x)+a}} \]
Antiderivative was successfully verified.
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Rule 3319
Rule 4181
Rule 2531
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int \frac{x^2}{\sqrt{a+a \cos (c+d x)}} \, dx &=\frac{\sin \left (\frac{1}{2} \left (c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{d x}{2}\right ) \int x^2 \csc \left (\frac{1}{2} \left (c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{d x}{2}\right ) \, dx}{\sqrt{a+a \cos (c+d x)}}\\ &=-\frac{4 i x^2 \tan ^{-1}\left (e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d \sqrt{a+a \cos (c+d x)}}-\frac{\left (4 \sin \left (\frac{1}{2} \left (c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{d x}{2}\right )\right ) \int x \log \left (1-i e^{i \left (\frac{c}{2}+\frac{d x}{2}\right )}\right ) \, dx}{d \sqrt{a+a \cos (c+d x)}}+\frac{\left (4 \sin \left (\frac{1}{2} \left (c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{d x}{2}\right )\right ) \int x \log \left (1+i e^{i \left (\frac{c}{2}+\frac{d x}{2}\right )}\right ) \, dx}{d \sqrt{a+a \cos (c+d x)}}\\ &=-\frac{4 i x^2 \tan ^{-1}\left (e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d \sqrt{a+a \cos (c+d x)}}+\frac{8 i x \cos \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (-i e^{\frac{1}{2} i (c+d x)}\right )}{d^2 \sqrt{a+a \cos (c+d x)}}-\frac{8 i x \cos \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (i e^{\frac{1}{2} i (c+d x)}\right )}{d^2 \sqrt{a+a \cos (c+d x)}}-\frac{\left (8 i \sin \left (\frac{1}{2} \left (c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{d x}{2}\right )\right ) \int \text{Li}_2\left (-i e^{i \left (\frac{c}{2}+\frac{d x}{2}\right )}\right ) \, dx}{d^2 \sqrt{a+a \cos (c+d x)}}+\frac{\left (8 i \sin \left (\frac{1}{2} \left (c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{d x}{2}\right )\right ) \int \text{Li}_2\left (i e^{i \left (\frac{c}{2}+\frac{d x}{2}\right )}\right ) \, dx}{d^2 \sqrt{a+a \cos (c+d x)}}\\ &=-\frac{4 i x^2 \tan ^{-1}\left (e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d \sqrt{a+a \cos (c+d x)}}+\frac{8 i x \cos \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (-i e^{\frac{1}{2} i (c+d x)}\right )}{d^2 \sqrt{a+a \cos (c+d x)}}-\frac{8 i x \cos \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (i e^{\frac{1}{2} i (c+d x)}\right )}{d^2 \sqrt{a+a \cos (c+d x)}}-\frac{\left (16 \sin \left (\frac{1}{2} \left (c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{d x}{2}\right )\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(-i x)}{x} \, dx,x,e^{i \left (\frac{c}{2}+\frac{d x}{2}\right )}\right )}{d^3 \sqrt{a+a \cos (c+d x)}}+\frac{\left (16 \sin \left (\frac{1}{2} \left (c+\frac{\pi }{2}\right )+\frac{\pi }{4}+\frac{d x}{2}\right )\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(i x)}{x} \, dx,x,e^{i \left (\frac{c}{2}+\frac{d x}{2}\right )}\right )}{d^3 \sqrt{a+a \cos (c+d x)}}\\ &=-\frac{4 i x^2 \tan ^{-1}\left (e^{\frac{1}{2} i (c+d x)}\right ) \cos \left (\frac{c}{2}+\frac{d x}{2}\right )}{d \sqrt{a+a \cos (c+d x)}}+\frac{8 i x \cos \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (-i e^{\frac{1}{2} i (c+d x)}\right )}{d^2 \sqrt{a+a \cos (c+d x)}}-\frac{8 i x \cos \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_2\left (i e^{\frac{1}{2} i (c+d x)}\right )}{d^2 \sqrt{a+a \cos (c+d x)}}-\frac{16 \cos \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_3\left (-i e^{\frac{1}{2} i (c+d x)}\right )}{d^3 \sqrt{a+a \cos (c+d x)}}+\frac{16 \cos \left (\frac{c}{2}+\frac{d x}{2}\right ) \text{Li}_3\left (i e^{\frac{1}{2} i (c+d x)}\right )}{d^3 \sqrt{a+a \cos (c+d x)}}\\ \end{align*}
Mathematica [A] time = 0.0766249, size = 146, normalized size = 0.56 \[ \frac{4 \cos \left (\frac{1}{2} (c+d x)\right ) \left (-i d^2 x^2 \tan ^{-1}\left (e^{\frac{1}{2} i (c+d x)}\right )+2 i d x \text{Li}_2\left (-i e^{\frac{1}{2} i (c+d x)}\right )-2 i d x \text{Li}_2\left (i e^{\frac{1}{2} i (c+d x)}\right )-4 \text{Li}_3\left (-i e^{\frac{1}{2} i (c+d x)}\right )+4 \text{Li}_3\left (i e^{\frac{1}{2} i (c+d x)}\right )\right )}{d^3 \sqrt{a (\cos (c+d x)+1)}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.184, size = 0, normalized size = 0. \begin{align*} \int{{x}^{2}{\frac{1}{\sqrt{a+\cos \left ( dx+c \right ) a}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{x^{2}}{\sqrt{a \cos \left (d x + c\right ) + a}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{\sqrt{a \left (\cos{\left (c + d x \right )} + 1\right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{\sqrt{a \cos \left (d x + c\right ) + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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